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`(sqrt(2gh))/(2)``sqrt(2gh)``sqrt(gh)``(sqrt(gh))/(2)`

Answer :

CSolution :

`(` work done by gravity `-` work done by friction `) =` change in `K.E.` <br> `:. Mgh - mu mg`` (x_(0))/(2)=(1)/(2)mv_(1)^(2)-(1)/(2)mv_(1)^(2)` <br> `=mgh-(h)/(x_(0))mg``(x_(0))/(2)=(1)/(2) mv_(1)^(2)-0 :' mu=(h)/(x_(0))` <br> `:. (mgh)/(2)=(1)/(2)mv_(1)^(2)rArr v_(f)=sqrt(gh)`